Solution Applications
20.00 mL of the barium chloride solution required 15.50 mL of the potassium sulfate solution to react completely. MK2SO4 = ?
BaCl2(aq) + K2SO4(aq) _ ? + ?
BaCl2(aq) + K2SO4 (aq) _ 2 KCl(aq) + BaSO4 (s)
?MK2SO4 = [MBaCl2x VBaCl2 / VK2SO4 ] [? molK2SO4 / ? molBaCl2 ]
0.010000 molBaCl2 x 0.02000 LBaCl2 x 1 molK2SO4
LBaCl2 x 0.01550 LK2SO4 x 1 molBaCl2
?MK2SO4 =
?MK2SO4 = 0.01290 molK2SO4 / LK2SO4 = 0.01290 MK2SO4
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