PPT Slide

Solution Applications

If 20.00 mL of a 0.10 M solution of barium chloride was reacted with 15.00 mL of a 0.20 M solution of potassium sulfate, what would be the theoretical yield of barium sulfate?

BaCl2(aq) + K2SO4 (aq) _ 2 KCl(aq) + BaSO4 (s)

Must use the limiting reagent:

0.10 molBaCl2 x 0.02000 LBaCl2 x 1 molBaSO4 x 233.39 g BaSO4

LBaCl2 1 molBaCl2 molBaSO4

=

= 0.47 g

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