Applying the Relationship Among Current, Time, and Amount of Substance
Problem: A technician needs to plate a bathroom fixture with 0.86 g of
chromium from an electrolytic bath containing aqueous Cr2(SO4)3. If
12.5 min is allowed for the plating, what current is needed?
Plan: We write the half-reaction for Cr3+ reduction. We then know the
number of moles of electrons per mole of Cr, and can calculate the
current needed to do the electroplating.
Solution: Writing the balanced half-reaction:
Cr3+(aq) + 3 e- Cr(s)
e- transferred: 0.86 g Cr x x = 0.050 mol e-
1 mol Cr
52.00 g Cr
3 mol e-
1 mol Cr
Calculating charge transfer:
Charge (C) = 0.050 mol e- x = 4.8 x 103 C
9.65 x 104 C
1 mol e-
Calculating the current:
Current (A) = = x = 6.4 C/s = 6.4 A
charge (C)
time (s)
4.8 x 103 C
12.5 min
1 min
60 s
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