Predicting the Formation of a Precipitate
Solution continued
For CrO42- : [0.100 M Na2CrO4] [0.200 L] = 0.0200 mol CrO42-
Qsp = [Ba2+] [CrO42-] =(0.183 M Ba2+)(0.667 M CrO42-) = 0.121
Since Ksp = 2.1 x 10-10 and Qsp = 0.121, Qsp >> Ksp and a precipitate
will form.
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