Determining Solubility from Ksp
Ksp = 2.3 x 10-13 = [Pb2+] [CrO42-]
Concentration (M) PbCrO4 Pb2+ CrO42-
Initial ---------- 0 0
Change ---------- +x +x
Equilibrium ---------- x x
Ksp = [Pb2+] [CrO42-] = (x)(x ) = 2.3 x 10-13
x = 4.80 x 10-7
Therefore the solubility of PbCrO4 in water is 4.8 x 10-7 M
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